display two digit values

lian1238 · #1 27-Nov-2005, 00:53

Hi

Is there a way to display 2-digit values with cout?

WaltP · #2 27-Nov-2005, 01:22

Not easily. The simplest is

CPP / C++ / C Code:

if (num < 10)
{
    cout << '0';
}
cout << num;

cout is notoriously difficult to get formatted output. I find the iomanip flags and features to be tedious and limiting.
printf is much better but C++ snobs and zealots don't like using it for some reason.

For the hard way, check out this link

Paramesh · #3 27-Nov-2005, 08:39

Quote:

Originally Posted by lian1238

Hi

Is there a way to display 2-digit values with cout?

Yes. cout itself prints any 2 digit value.

Please explain more clearly what you want.

Paramesh.

PS: Just a joke.

lian1238 · #4 27-Nov-2005, 11:16

WaltP, thx for the link.

Paramesh, I dun really get your joke but.. it's good to joke!

alcoholic · #5 28-Nov-2005, 08:54

Quote:

Originally Posted by lian1238

Hi

Is there a way to display 2-digit values with cout?

Yes plz explain in detail what u want...it seems a very trivial question

lian1238 · #6 28-Nov-2005, 10:46

first, sorry I wasn't very clear in the first place.
second, is it really a trivial question?
third, what I'm saying is that, if you had a number, say 2, and wanted to display "02", how would you do it with cout?
well, WaltP said you can do it like this:

CPP / C++ / C Code:

if (num < 10)
{
    cout << '0';
}
cout << num;

that wasn't very hard. but, what if you wanted to display 2 as "0000000002"?? (a ten-digit number).. that'd be more tedious, not necessarily harder.

I hope I've made myself more clear.

Paramesh · #7 28-Nov-2005, 11:11

Quote:

Originally Posted by lian

but, what if you wanted to display 2 as "0000000002"?? (a ten-digit number).. that'd be more tedious, not necessarily harder.

We can use the fill and width options in cout to do this.
No need to use iomanip!

For example, insert this code:

CPP / C++ / C Code:

    int i = 2;

    cout.fill('0');       // fill available spaces with 0  
    cout.width(10);  // set the width as 10

    cout<< i;           // print the value and see whats your output

Will print nine '0's before 2.
The output will be like:

Code:

0000000002

Regards,

Paramesh.

WaltP · #8 28-Nov-2005, 13:07

Quote:

Originally Posted by Paramesh

We can use the fill and width options in cout to do this.
No need to use iomanip!

I was including these [kbd]cout[/jbd] methods as part of iomanip. My unfortunate lack of detailed knowledge. My dislike still holds -- these methods seem so awkward to me. Formatting cout is awkward, tedious, and limiting.

The printf() function is so much easier and straight forward...

WaltP · #9 28-Nov-2005, 13:27

I have an ongoing challenge that noone's solved. The challenge is
Convert this printf() statement into readable C++, output must match exactly:

CPP / C++ / C Code:

int iVal = 2;
int hVal= 0x0C;
char *filename = "test.fil";
char *username = "juser";
float fValue23.8;
printf("%4d  0x%02X  Testfile: [%10s]  user: [%-10s]\nTrial %8.2f \n", 
        iVal, hVal, filename, username, fValue);

Output

CPP / C++ / C Code:

   2  0x0C  Testfile: [  test.fil]  user: [juser     ]
Trial    23.80

taken from a previous post

Sokar · #10 28-Nov-2005, 21:35

Quote:

Originally Posted by WaltP

output must match exactly:

I get this for output with your code.
walts_conjured_up_code.cpp(17) : error C2143: syntax error : missing ';' before 'constant'
Ok here you go,

CPP / C++ / C Code:

int main()
{
	float fValue23.8;
	return 0;
}

mycode.cpp(17) : error C2143: syntax error : missing ';' before 'constant'
I win. What do I win?

Quote:

Originally Posted by WaltP

taken from a previous post

Whenever you post that code it always has the same error. It seems like you would have fixed that by now.

Quote:

Originally Posted by WaltP

I have an ongoing challenge that noone's solved. The challenge is
Convert this printf() statement into readable C++, output must match exactly:

In all seriousness readable is subjective, as is convert, so here you go,

CPP / C++ / C Code:

#include <iostream>
#include <string>

using namespace std;

int main()
{
	int iVal = 2;
	int hVal= 0x0C;
	char *filename = "test.fil";
	char *username = "juser";
	float fValue = 23.8f;

	printf("%4d  0x%02X  Testfile: [%10s]  user: [%-10s]\nTrial %8.2f \n", 
		iVal, hVal, filename, username, fValue);

	cout << "   " << iVal << "  0x0";
	cout << hex << uppercase << hVal;

	string tfilename(filename);
	string tusername(username);
	cout << "  Testfile: [  " << tfilename << "]  user: ["
		<< tusername << "     ]\n";
	cout.precision(4);
	cout << "Trial    " << showpoint << fValue << endl;

	return 0;
}

I will not debate whether you have a valid point or not.
But most C++ user will use string not *char, so you have deliberately created more problems with your conjured up example than need be. So what you are trying to accomplish. Your gripe seems to be formating. So before you go and start talking about performance and code bulk with what I posted, I am not interested. You should ask the OP if what you posted is more readable. You know the answer will be no.

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