how do i find(list them) and sum them up?

jack223 · #1 03-Nov-2005, 14:09

here is what i have so far...i need to list all the odd number and sum them up at the end....any help please.

CPP / C++ / C Code:

#include <iostream>

using std::cout;

using std::cin;

using std::endl;

#include <iomanip>

using std::setw;


const int MAX = 10;


int main()

{

int odd = 0;

	int MyArray[MAX] = {2, 3, 4, 5, 7, 10, 23, 45, 50, 77}; 


	int odd = 0;

	for (int i = 0; i < MAX; i++)
	{	MyArray[i];

		if ((MyArray[i] % 2) == 0)
		{
			odd++;
		}
	}


	cout << "Element" << setw(13) << "Value" << endl;
	
	for ( int j = 0; j < MAX; j++)
		cout << setw(7) << j << set(13) << MyArray[j] << endl;

	cout << "Count odd numbers: " << odd << "\n" << endl;
	
	return 0 ;
}

Paramesh · #2 03-Nov-2005, 15:42

Hi jack,

Welcome to the GID Forums.
Did you read the guidelines?

Quote:

here is what i have so far...i need to list all the odd number and sum them up at the end....any help please.

So, to sum all the odd numbers, we can have an extra variable called sum.
the sum is initialized to zero at the start.

CPP / C++ / C Code:

    int sum = 0;

Then, to check whether a number is odd or not, we have to use like this:

CPP / C++ / C Code:

if ( ( MyArray[ i ] % 2 ) == 1 )

because % will give us the remainder when dividing a number.
For example, consider that we have 5.
5 % 2 will be 1. whereas
4 % 2 will be 0.

So, the remainder should be 1 for odd number.

Now, how to calculate the sum?
We can calculate the sum when we count the odd numbers itself.
like this:

CPP / C++ / C Code:


for (int i = 0; i < MAX; i++)
{

if ((MyArray[i] % 2) == 1)
{
odd++;
sum += MyArray[i];
}

}

Then you can display the count and sum in the end.

Here is what you should remove:
1. The extra int odd = 0; You can declare a variable only once.
So, you can use int sum = 0; instead.
2. In the for loop:

CPP / C++ / C Code:

for (int i = 0; i < MAX; i++)
{ MyArray[i];

there is no need for that MyArray[i] here. You can remove it.
3. In this line:

CPP / C++ / C Code:

cout << setw(7) << j << set(13) << MyArray[j] << endl;

the set should be setw.

In the next line,

CPP / C++ / C Code:

cout << "Count odd numbers: " << odd << "\n" << endl;

We can use endl instead of "\n".

Summarising, here is the code

CPP / C++ / C Code:

int sum = 0;

for (int i = 0; i < MAX; i++ )
{ 
    if ( ( MyArray[ i ] % 2 ) == 1 ) //check whether the number is odd or not.
    {
       odd++;                       //increase the odd number count
       sum += MyArray[i];       //add the odd numbers
    }
}

Regards,
Paramesh.

jack223 · #3 03-Nov-2005, 16:25

thanks Paramesh.

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how do i find(list them) and sum them up?

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