A 'not' regex

Allowee · #1 07-Jun-2003, 15:24

I got this code here..

PHP Code:


<?php$message['body'] = preg_replace('_\[php\](.*?)\[/php\]_ise', "parseEmoticons('$1')", $message['body']);?>

but that will only parse emoticons when there are php tags.

I'm looking for a 'not' code.

so when there isn't a php code tag it will parse, and not in the php tags.

just look at the code below......

PHP Code:


<?phpecho ":)";// test :( [this is : ( ]?>

JdS · #2 07-Jun-2003, 20:20

I have not found an easier way to do what you're trying to do but for now this is what I can suggest.

PHP Code:


<?php
// this array will store the markers and the replacements
$replacements = array();

// the list of smilies and their replacements
$smilies = array(
 ':)'=>'<img src="images/smilies/smile.gif" border="0" alt="">',
 ':('=>'<img src="images/smilies/frown.gif" border="0" alt="">'
);

// do the code highlighting first and place markers
$message['body'] = preg_replace('_\[php\](.*)\[/php\]_ise', "parsePHP('$1')", $message['body']);
// do the smilies
$message['body'] = strtr( $message['body'], $smilies );

// lastly, replace markers with whatever is in $replacements
$message['body'] = strtr( $message['body'], $replacements );

// unset large arrays
unset( $smilies, $replacements );

// the function parsePHP()
function parsePHP( $str )
{
  $mark = marker( 'PHP' );
  $str = highlight_string( $str, 1 );
  // add the marker and highlighted code into our $replacements array
  $GLOBALS['replacements']["$mark"] = $str;
  return $mark;
}

// the function marker()
function marker( $name )
{
  static $counter;
  ++$counter;
  return ( '['.$name.$counter.']' );
}
?>

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A 'not' regex

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