ask looping

likeit · #1 24-Jul-2005, 20:33

i have a problem bout looping so the output prog like this:

1
11
111
1111

*
**
***
****
*****

*
**
***
**
*
i have problem to make a prog with algorithm and code-code,if u have any tips or from ur experience to create prog with quick ,pls share .thanks

Dave Sinkula · #2 24-Jul-2005, 20:49

Quote:

Originally Posted by likeit

i have a problem bout looping so the output prog like this:

Would you care to share the problem with the rest of us? Or are we supposed to write your homework assignment for you? Why not just post your instructor's email so we can send it in directly?

[edit]Post what you have worked on, and folks will improve on it from there.

alcedo · #3 26-Jul-2005, 11:38

Hmm how are we going to know the nature of the question you are asking ? and the problems you faced while doing the question?

likeit · #4 26-Jul-2005, 19:14

i figure out the looping like this:
j=0 1 2 3
---------------
i=0 | 1
1 | 1 1
2 | 1 1 1
3 | 1 1 1 1

here is the code :

CPP / C++ / C Code:

#include<stdio.h>
#include<conio.h>
main(){
int a,i,j;
printf("many looping:");
scanf("%d",&a);
for(i=0;i<a;i++)
 for(j=0;j<a;j++)
   printf("1");
   printf("");
printf("\n");
getch();
return 0;
}

the output is :
1

i spend many time to find the design but it's hard to find the correct,can anyone help?

WaltP · #5 26-Jul-2005, 19:49

Quote:

Originally Posted by likeit

i figure out the looping like this:
j=0 1 2 3
---------------
i=0 | 1
1 | 1 1
2 | 1 1 1
3 | 1 1 1 1

here is the code :

CPP / C++ / C Code:

#include<stdio.h>
#include<conio.h>
main(){
int a,i,j;
printf("many looping:");
scanf("%d",&a);
for(i=0;i<a;i++)
 for(j=0;j<a;j++)
   printf("1");
   printf("");
printf("\n");
getch();
return 0;
}

the output is :
1

i spend many time to find the design but it's hard to find the correct,can anyone help?

Here's what I get when I run it:

Quote:

many looping:4
1111111111111111

which is exactly what I expected.

Since I'm note sure what you're thoughts are I'm not sure what you're trying to accomplish in the code. My first suggestion is to put braces around your for statements. I'll comment what you've got and maybe you can see what you need to do, or ask about.

CPP / C++ / C Code:

#include<stdio.h>
#include<conio.h>
main(){
int a,i,j;
printf("many looping:");
scanf("%d",&a);
for(i=0;i<a;i++)    // outer loop for row
{
 for(j=0;j<a;j++)   // inner loop for column
 {
   printf("1");  // always output a '1' for each position
 }
}
   printf("");   // when done, output a nuthing (empty string)
printf("\n");   // next line
getch();
return 0;
}

So first off, rearrange the braces so you start getting the lines correct.

Then you have to decide how to tell if you need to output a '1', and empty string, or another character. I'd recommend outputting a '0' or '-' until you get the pattern right:
1---
11--
111-
1111

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