Program output in wrong order

strangr314 · #1 08-Jul-2005, 07:48

When i use a combination of cout and printf statements, the program does not seem to read them from top to bottom as it moves down the program. It seems to see and evaluate the printf's first. Anyone know why this happens? The output i get when i run the following code is:

Line2
Line4
Line1
Line3

I thought i should be getting :
Line1
Line2
Line3
Line4

CPP / C++ / C Code:

	
		#include <stdio.h>
		#include <stdlib.h>
		#include <iostream.h>

	void main()
{
		cout << "\nLine1";
		printf("\nLine2");
		cout << "\nLine3";
		printf("\nLine4");
	exit(0);

}

Dave Sinkula · #2 08-Jul-2005, 08:11

In general, I don't think it's a good idea to mix the two, but here's something to try.

strangr314 · #3 08-Jul-2005, 08:16

Thanks! Putting in the line of code suggested on that page solved the problem. I'm only using the cout to help me make sure the program is working properly so i shouldn't need it in the end.

Thanks Again!

WaltP · #4 08-Jul-2005, 12:42

Quote:

Originally Posted by strangr314

Thanks! Putting in the line of code suggested on that page solved the problem. I'm only using the cout to help me make sure the program is working properly so i shouldn't need it in the end.

Thanks Again!

You'd be better off changing the cout to printf()/puts() even in the beginning. No sense hitting your head against the wall because your debugging is throwing off your code/data. Stick with one or the other but never mix two differen output styles in a program. As you've seen, headache-city!

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