Creating A Graph In C

lilmainy · #1 20-Apr-2005, 10:40

Hi All Again

I have produced a program so far that creates an '*' for an equation thus code is below.. but now i wish too add x and y axis and numbers to the program any ideas i am really struggling. Question and My Answer So Far Below:

QUESTION

Write a program that displays the graph of the following equation

Y=X+10

The program should first ask the user for:
1. the X axis starting point
2. the number of steps
3. step-size

It should then repeatedly calculate the value of Y using the changing value of X. Normally, X increases by the step size for the number of steps specified. The program should display an ‘*’ in each X column to denote the Y value, e.g. if Y = 10, then the 10th element of an 81 element character array should be set to ‘*’ and then the string printed to the screen. All other elements should be a space character (“ “), except the last, which should be the null character to make it a string. If the value of Y goes over 80, then the program should put a ‘^’ hat character in the 79th (second to last) element of the array. If the value goes under 0 (zero), then the program should put a 0 (zero) in the 0 (first) element of the array.

Add axis to the graph using

a) ‘-‘ (minus) character for the Y axis
b) ‘|’ (pipe) character for the X axis
c) ‘+’ character in the lower left to show where they intersect at 0,0

Add numbers to the X and Y axis. The numbers on the X axis should be dictated by the user input.

MY ANSWER SO FAR

CPP / C++ / C Code:


#include <stdio.h>
#include <string.h>
int main(void)
{
  /* Delclaring Varibles */
  char str[81];
  int start, stepsize, steps;
  int x, y;

  /* Initialize the last char to \0 */
  str[80] = '\0';

  /* Get the parameters from the user */
  printf("please enter x axis starting point: ");
  scanf("%d", &start);
  printf("You entered %d\n", start);
  printf("please enter stepsize: ");
  scanf("%d", &stepsize);
  printf("You entered %d\n", stepsize);
  printf("please enter no of steps: ");
  scanf("%d", &steps);
  printf("You entered %d\n", steps);

  /* For Loop */
  for (x = start; x < steps; x += stepsize)
  {
    /* initialize the array */
    memset(str, ' ', 80);

    /* Compute y */
    y = x + 10;
    printf("x = %d, y = %d\n", x, y);

   /* make sure y isn't over the limits */
  if (y > 80)
  {
    /* hat in the 79th element of the array */
    str[79] = '^';
   }
   /* checking if y is less than 0 */
  else if (y < 0)
  {
    str[0] = 0;
  }
    /* Set the appropriate char to */
  else
  {
    str[y] = '*';
    str[y+1] = '\0';
  }

    /* Print the result */
    printf("%s\n", str);
  }
  getch();
}

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