Originally Posted by mccrbr01

This problem involves calculating the value of Pi from the infinite series: 4-4/3+4/5+4/7+4/9-4/11+...
I have successfully created a program that creates the values of Pi for the first eleven terms of the series. I now need to create a program that determines and prints how many terms of the series you have to use before you first get:
a. 3.14?
b. 3.141?
c. 3.1415?
d. 3.14159?
e. 3.14159265358979?

The program should use break and continue statements. My code is given below. Two changes I know it needs (but not sure the best way to do) are:
1. Use a larger array
2. Consider the correct number of decimal positions

#include <stdio.h>
#include <math.h>
int main ()
{
int i; /* counter */
double pi[11];
double n;
double p;
int term = 0;
double plus = 0;
double minus = 0;

printf ("%7s%20s\n", "# Of Terms", "Values of Pi");

for(i=0; i<11; i++){

p=0;
plus=0;
for (p=0; p<=i; p+=2){
plus = plus + 4 / (1+2*p);
} /* end for */

n=1;
minus=0;
for (n=1; n<=i; n+=2){
minus = minus - 4 / (1+2*n);
} /* end for */

term = i + 1;
pi = minus + plus;

if (pi == 3.14){
printf("%7d%20f\n", term, pi);
continue;
} /* end if */

if (pi == 3.141){
printf("%7d%20f\n", term, pi);
continue;
} /* end if */


if (pi == 3.14159265358979){
printf("%7d%20f\n", term, pi);
break;
} /* end if */

} /* end for */

return 0;
}