<? 
mysql_select_db($dbname, $link); 
$result=mysql_query("select * from user_detail where nickname = '$name'") ; 
$number_of_array = mysql_num_rows($result); 
while ($number_of_array = mysql_fetch_array($result)){ 
echo"<img src=\"./image/$number_of_array[image_name]\">"; 
}             
?>