hello,

I need to convert a double (20 with 4 digits after decimal) to char [20].

can any oen help.

thank you
kilgor

this has been discussed in a thread recently. click below:
previous thread

And once again, I think that sprintf is the easiest way to do this. I wrote custom functions to do this when I found out that itoa nad ftoa are not standard functions and the *suck* compared to sprintf (my opinion).


Cheers,
d

i just tried it but got this error
double errcnt = 0;
char num_errcnt[13];
int fillstruct();

int main()
{
fillstruct();

return(0);
}

int fillstruct()
{
int x;
strcpy(num_errcnt, "000006789012");
errcnt = atof(num_errcnt);
cout << "numerr " << num_errcnt[11] << endl;
cout << "prefix " << errcnt << endl;
strcpy(num_errcnt, "000000000000");
cout << "before " << num_errcnt << endl;
sprintf(num_errcnt, "%20.4f", errcnt);
cout << "after " << num_errcnt << endl;
cin >> x;
return(0);
}
error: implicit declaration of function 'int sprintf(...)

you probably dint include the proper header file for sprintf. which is it???? ask dsmith!

I agree mach. (But I usually agree with you anyway )

try:

hm.. thats weird. i just tried it without including stdio.h and it worked. probably because i used namespace std. by the way, why are you CINing x but not doing anything with it? did you mean to return x?

also whats weird is that your compiler assumes that sprintf is of type int!

This is a typical error when you don't have a function definition because C/C++ assumes that it returns an int.

Not only that but sprintf() does return an int... ;-)

__________________

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what do you know! c++ "assumed" something correctly!

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