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#1
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moderatorhow can i become a moderator here?
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#2
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One must prove oneself in three ways:
- courage - loyalty - highspeed net connection & plenty of time on one's hands. |
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#3
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Quote:
OK, give me a test for courage and loyalty, as for high speed connection i have cable modem, and I have plenty of time on my hands, which i'd rather not spend gaming |
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#4
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You also must solve this problem:
An airline requires that all rectangular packages that are carried on an airplane by passengers have the sum of the three dimensions be at most 120 centimeters. You must find the dimensions(all dimensions) of the square-ended side of the rectangular package of greatest volume, that meets the requirements above. __________________
Mr. Bob's Web Design - Tirelessly looking for ways to enhance the customer base of your business. |
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#5
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Quote:
i thought rectangular packages had six dimensions or sides. and what do you mean by square-ended side? i thought this was a rectangular package! |
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#6
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that was awfully stupid of me to make that reply. I thought it was a trick question, perhaps i was paranoid from being high on c++ or something. Very challenging problem atleast for me; i think it requires calculus(which i dont know), and currently i don't have much idea on how to solve it elegantly and accurately. I can only speculate. However, here goes: all three dimensions can at max have a sum of 120 cm so x+y+z = 120 cm now given that the rectangle has a square side, it must atleast have 2, and at max have all 6 sides as squares. so x = y, 2x + z = 120cm the following would require calculus, and im just guessing answers. so to find V, (x^2) *z ?= max; i tried a few different values for dimensions where 2x + z =120 and i found that 40*40*40 yields 64000 cm^3, which is the greatest volume i've been able to find with different values. so the rectangular box is a cube, atleast according to my guess. so there you have it. I will try and look thru some calculus and see if i can find an elegant and efficient way to solve this, but it might take time |
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#7
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You are on the right track. You had to take a derivative of some equation.
My answer was 30 30 60 though. __________________
Mr. Bob's Web Design - Tirelessly looking for ways to enhance the customer base of your business. |
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#8
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I am sorry your question was not answered properly.
Straight to the point - we ARE always looking for moderators. You don't apply to be one, you get invited in. More details: We (the existing team of moderators) want to collectively decide who to approach and invite into our fold. Not one of our existing team members ever applied to be a moderator - this is a fact. Every one of them was invited and voted in. We generally look for members who (can) visit the forums at least once a day, is genuinely helpful, pleasant and patient. We don't require you to be an expert at all but it's obviously a plus factor. In a nutshell - don't call us, we'll call you... ![]() __________________
J de Silva Learning Journal | GIDForums™ | GIDNetwork™ | GIDWebhosts™ | GIDSearch™ |
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#9
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Quote:
GF |
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#10
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Yes it is better. I did everything according to the book too lol!
After I turned in my test I found out that google has archived the answer somewhere, which shows that it is 40 40 40. __________________
Mr. Bob's Web Design - Tirelessly looking for ways to enhance the customer base of your business. |
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