Help with array and function input

FearlessFife35 · #1 11-Apr-2004, 17:22

I am having to write a program that determines the day number in a year for a date that is provided as input data. Like, if the user inputs January 1st, 2004...the program will output 1. I have some of it written and just can't seem to figure out the formula that computes the data...here is what I have written so far:

CPP / C++ / C Code:

#include <stdio.h>
void instructions(void);
int getdays(int, int, int);

int main(void)
{
	int month;
	int day;
	int year;

	instructions();
	printf("Please enter the month like this: for January..enter 1: ");
	scanf("%d", &month);
	printf("Please enter the day like this: for the fifth day..enter 5: ");
	scanf("%d", &day);
	printf("Please enter the year like this:2004....: ");
	scanf("%d", &year);

	printf("Here is the data you entered: %d/ %d/ %d\n", month, day, year);


	
	return 0;

}


void instructions(void)
{

	printf("This program will allow you to input any date such as, January 1, 2004.\n");
   printf("\n");
	printf("Once the date has been entered, the program will then tell you how\n");
	printf("many days have passed from the beginning of the calender year to\n");
	printf("the date you have entered.\n");
	printf("\n");
	printf("You will now be required to enter the month, day, and year using\
	        integers.\n");
	printf("\n\n");
}

int getdays(int m, d, y)
{
	int days[MONTHS] = {31,28,31,30,31,30,31,31,30,31,30,31};
	int x;
	int temp;
	int days = 0;

	for(x = 0; x < m; x++)
	{
	temp += MONTHS[x];
   	/*Here is where I'm having a problem figuring out how to do the formula*/

BlueTeeth · #2 11-Apr-2004, 18:18

CPP / C++ / C Code:

for(x = 0; x < m-1; x++)   //condition must be m-1 because days[0] stands for m=1
{
temp+=days[x];
}
temp+=d;
return temp;
//no need for variable days,and no need to pass year

WaltP · #3 11-Apr-2004, 22:48

Although the colors are pretty, we would prefer your code be within code tags ([c] & [/c]) to preserve your formatting.

CPP / C++ / C Code:

int getdays(int m, d, y)    // improper syntax
{
    int days[MONTHS] = {31,28,31,30,31,30,31,31,30,31,30,31};
    int x;
    int temp;
    int days = 0;  // This is already defined above as an array

From this point, one way to do it is:

start temp at 0
set m as an offset from 0 instead of 1 because the index for Jan = 0
loop from 0 to m-1 and accumulate the days of each month in temp (you don't want the last month added yet)
When the loop is finished, add d

and voila you have the julian date for the year. I'll let you figure out how to do the leap year.

FearlessFife35 · #4 15-Apr-2004, 14:45

Quote:

Originally Posted by WaltP

Although the colors are pretty, we would prefer your code be within code tags ([c] & [/c]) to preserve your formatting.

CPP / C++ / C Code:

int getdays(int m, d, y)    // improper syntax
{
    int days[MONTHS] = {31,28,31,30,31,30,31,31,30,31,30,31};
    int x;
    int temp;
    int days = 0;  // This is already defined above as an array

From this point, one way to do it is:

start temp at 0
set m as an offset from 0 instead of 1 because the index for Jan = 0
loop from 0 to m-1 and accumulate the days of each month in temp (you don't want the last month added yet)
When the loop is finished, add d

and voila you have the julian date for the year. I'll let you figure out how to do the leap year.

I have been doing some more work on this program, with your help....still not getting it to work. Could you take a look at it and give me some more advice? Thanks for any help!

CPP / C++ / C Code:

#include <stdio.h>
#define MONTHS 12
void instructions(void);
int getdays(int, int, int);
int LeapYear(int year);

int main(void)
{
	int month;
	int day;
	int year;
	int numdays;

  


	instructions();
	printf("Please enter the month like this: for January..enter 1: ");
	scanf("%d", &month);
	printf("Please enter the day like this: for the fifth day..enter 5: ");
	scanf("%d", &day);
	printf("Please enter the year like this:2004....: ");
	scanf("%d", &year);
	getdays(month,day,year);

	numdays = getdays(month, day, year);

  


	printf("The number of days passed since the date you've entered is: \n", numdays);


	
	return 0;

}


void instructions(void)
{

	printf("This program will allow you to input any date such as, January 1, 2004.\n");
	printf("\n");
	printf("Once the date has been entered, the program will then tell you how\n");
	printf("many days have passed from the beginning of the calender year to\n");
	printf("the date you have entered.\n");
	printf("\n");
	printf("You will now be required to enter the month, day, and year using\
	        integers.\n");
	printf("\n\n");
}

int getdays(int m,int d,int y)
{
	int days[MONTHS] = {31,28,31,30,31,30,31,31,30,31,30,31};
	int x;

	int dayCount = 0;

	for(x = 0; x < m; x++)
	{

		if(x==1)
			dayCount += days[x];
		{
		if(LeapYear(y) == 0)
			dayCount += days[x];
		else
			dayCount += 29;
    	else
			dayCount += d;
		}
	}
	return dayCount;
}

int LeapYear(int year)
{

	if((year % 400) == 0) || (((year % 4)  == 0) && ((year % 100) != 0));
	{
		return 0;
	else
		return 1;
	}
}
#include <stdio.h>
#define MONTHS 12
void instructions(void);
int getdays(int, int, int);
int LeapYear(int year);

int main(void)
{
	int month;
	int day;
	int year;
	int numdays;

  


	instructions();
	printf("Please enter the month like this: for January..enter 1: ");
	scanf("%d", &month);
	printf("Please enter the day like this: for the fifth day..enter 5: ");
	scanf("%d", &day);
	printf("Please enter the year like this:2004....: ");
	scanf("%d", &year);
	getdays(month,day,year);

	numdays = getdays(month, day, year);

  


	printf("The number of days passed since the date you've entered is: \n", numdays);


	
	return 0;

}


void instructions(void)
{

	printf("This program will allow you to input any date such as, January 1, 2004.\n");
	printf("\n");
	printf("Once the date has been entered, the program will then tell you how\n");
	printf("many days have passed from the beginning of the calender year to\n");
	printf("the date you have entered.\n");
	printf("\n");
	printf("You will now be required to enter the month, day, and year using\
	        integers.\n");
	printf("\n\n");
}

int getdays(int m,int d,int y)
{
	int days[MONTHS] = {31,28,31,30,31,30,31,31,30,31,30,31};
	int x;

	int dayCount = 0;

	for(x = 0; x < m; x++)
	{

		if(x==1)
			dayCount += days[x];
		{
		if(LeapYear(y) == 0)
			dayCount += days[x];
		else
			dayCount += 29;
    	else
			dayCount += d;
		}
	}
	return dayCount;
}

int LeapYear(int year)
{

	if((year % 400) == 0) || (((year % 4)  == 0) && ((year % 100) != 0));
	{
		return 0;
	else
		return 1;
	}
}

)

aaroncohn · #5 15-Apr-2004, 19:33

What is it you want to hear? Please ask a specific question, because I'd rather not look through all that code without knowing what the problem is first!

BlueTeeth · #6 15-Apr-2004, 20:09

In the leap year the only difference is that Feb is 29 days so why don`t u check for leap year out of the loop and change the entry of feb. to 29 if it`s satisfied
and plz ask a specific question as said

Max Payne · #7 15-Apr-2004, 20:17

You code looks soo long that i refused to look, but on second look, it actually is a same code posted twice. Anyway, this is what I saw in your code.

CPP / C++ / C Code:

int getdays(int m,int d,int y)
{
  int days[MONTHS] = {31,28,31,30,31,30,31,31,30,31,30,31};
  int x;

  int dayCount = 0;

  for(x = 0; x < m-1; x++)
  {
    if(x==1) //for second month only (FEB)
    {
        if(y%4 != 0) //not leap year
           dayCount += days[x];
        else
           dayCount += 29; // yep. its leap year
    }
    else
      dayCount += days[x]; //other months, don't care, just add
  }
  dayCount+=d; //add remainning day.
  return dayCount;
}

Why do you make your leap year code like that :

CPP / C++ / C Code:

if((year % 400) == 0) || (((year % 4)  == 0) && ((year % 100) != 0));
  {
    return 0;
  else
    return 1;
  }

WaltP · #8 15-Apr-2004, 23:18

Quote:

Originally Posted by Max Payne

Why do you make your leap year code like that :

CPP / C++ / C Code:

if((year % 400) == 0) || (((year % 4)  == 0) && ((year % 100) != 0));
  {
    return 0;
  else
    return 1;
  }

Because that's how you decide if Feb has an extra day or not. But you have to format the if correctly:

CPP / C++ / C Code:

if(((year % 400) == 0) || (((year % 4)  == 0) && ((year % 100) != 0)))
    return 1;
else
    return 0;

Max Payne · #9 16-Apr-2004, 00:15

Quote:

Originally Posted by WaltP

Because that's how you decide if Feb has an extra day or not. But you have to format the if correctly:

Yes I know that. Buts isn't enough just like this:

CPP / C++ / C Code:

if(year%4==0)
    return 1;
else
    return 0;

Just curious.

Garth Farley · #10 16-Apr-2004, 04:24

Quote:

Originally Posted by Max Payne

Yes I know that. Buts isn't enough just like this:

CPP / C++ / C Code:

if(year%4==0)
    return 1;
else
    return 0;

Just curious.

No, considering the 'hundred years', there's a leap year only every 400 years. Like there was leap year in 2000, but not in 1900.
GF

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Help with array and function input

Thanks...But a little more help?