Troubles getting correct output

d0ll3rb1ll · #1 03-Nov-2009, 22:48

I want to add the numbers between x and y and not include x and y. So for example if x was 5 and y 9 the sum would be 21. When I run the program the output is 0. Hopefully someone can help me. I use the gcc compiler.

CPP / C++ / C Code:

#include <stdio.h>

int main (void)
{
        double x, y, sum, z;

        printf("Enter the value of x: \n");
        printf("Enter a  value larger than x for  y: \n");
                scanf("&lf &lf", &x, &y);

        sum = 0;

        for((z = (x + 1)); (x < z && z < y); z++)
                {
                        sum = z + sum;

                }

        printf("%f\n", sum);


return 0;
}

Howard_L · #2 04-Nov-2009, 00:12

Please TAKE THE TIME AND EFFORT TO USE THE C++ TAGS TO ENCLOSE THE CODE YOU SEND! ... read the guidelines.

If you used full warnings when you compile you program you might see:

Code:

~>  gcc -Wall -W -pedantic prog-1.c -o prog-1
prog-1.c: In function ‘int main()’:
prog-1.c:9: warning: too many arguments for format

which is refering to:

CPP / C++ / C Code:

scanf("&lf &lf", &x, &y);

The problem there is that you used &lf instead of the correct format specifier symbol %lf .
I think you might rather do that section like this:

CPP / C++ / C Code:

  printf("Enter the value of x: \n");
  scanf("%lf", &x);
  printf("Enter a value larger than x for y: \n");
  scanf("%lf", &y);

Try that and see if it runs a little better.

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Troubles getting correct output

Re: Troubles getting correct output