Re: How do I add arrays into my program?!?!

Howard_L · #11 28-Oct-2009, 23:26

Well the output I get is:

Code:

Please input 's' for series OR 'p' for resistors parallel
s
Please enter the number of resistors connected
3
Input value of  series resistor number 1
2.34
Input value of  series resistor number 2
4.6
Input value of  series resistor number 3
2.5
Resistor: 6
Resistor: 6
Resistor: 6
Resistor: 6
Resistor: 6
Resistor: 6
The total resistance is less than 1000 and its value is 9.44 Ohm

...and you would like to see something like (from above):

Code:

For series: (Example)
Total series resistance is 2.123 kOhm for 3 resistors:
1000 kOhm, 1000 kOhm, 123 kOhm

For parallel: (Example)
Total series resistance is 500 Ohm for 2 resistors:
1000 Ohm, 1000 Ohm

Well , for one thing you have this loop:

CPP / C++ / C Code:

    int array [] = {1,2,3,4,5,6};
    int length = sizeof(array) / sizeof(int);
    for(int i = 0; i < length; i++)
    {
      cout << "Resistor: " << length << endl;
    }

...before the "Total resistance ..." line.
For another you print the array "length" and an endl; what did you expect to see?
Why aren't you using the array r[] and iterating the "number_of_resistors_connected" times?
...as far as the endl; goes you should dump that and print something like " Ohm, " or somesuch to go between each value.

sl02ggp · #12 29-Oct-2009, 00:28

thanks! should be r[i]....and what do you mean by "," instead of endl?

also most of the time when setting up an array
the values are listed like this:
121
3434

how do i get it like this: 121, 3434

and how do i make my program realize i have input "blank" number of resistors for when it says

Total series resistance is 2.123 kOhm for "3" resistors:
1000 kOhm, 1000 kOhm, 123 kOhm

Howard_L · #13 29-Oct-2009, 01:14

I think this will give you some ideas to start with.
Add stuff to customize to your liking and then incorporate it into your program:

CPP / C++ / C Code:

#include <iostream>  /* printing arrays 101 */
using namespace std;

int main()
{
  int i, number_of_resistors_connected = 4;
  double r[5] = {1.5, 2.3, 4.5, 6.4, 0 };

  for ( i = 0; i < number_of_resistors_connected; i++)
  {
    cout << r[i] << " Ohm";
    if (i < number_of_resistors_connected - 1)
    {
      cout << ", ";
    }
  }
  cout << endl;
  return 0;
}

zalezog · #14 29-Oct-2009, 10:29

The program still wouldn't work the way you want it to.
THe formula for parallel resiatance should be:

CPP / C++ / C Code:

if (type == 'p') {
           total_resistance = 0.0;
            for (int i = 0; i < number_of_resistors_connected; i++) {
                cout << "Input value of  parallel resistor number " << i + 1 << endl;
                cin >> r[i];
                if (!cin || r[i] == 0) {
                    cout << "Invalid input." << endl;

                }
                total_resistance += 1 / r[i];
            }
        }
	}

The while loop should have a particular condition to continue.

CPP / C++ / C Code:

    char yes_no = 'y';
    while (yes_no == 'y' || yes_no == 'Y') {
    .
    .
    .
         // get user input whether to continue or not
        //Also delete the memory allocated :delete[]r
       //If you are using character input along with integer input
      //flush the buffer before beginning the next iteration.
       
    }

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