Convert to structure

chekers · #1 13-Oct-2009, 10:55

anyone can help me to convert this c coding to a structure...i dont know how to do it...Plz help me....

CPP / C++ / C Code:

#include <stdio.h>
#include <string.h>

void input_name(char name[][10], int stud, float mark_cs1[], float mark_cs2[], float mark_cs3[],int ch_cs1[],int ch_cs2[],int ch_cs3[],float gpa[]);
void input_mark(float mark1[], float mark2[], float mark3[], int i);
void calculate_gpa(float mark1[],float mark2[],float mark3[],int i,float gpa[],int ch_cs1[],int ch_cs2[],int ch_cs3[]);
void input_credithr(int ch_cs1[],int ch_cs2[],int ch_cs3[],int i);
void get_gradepoint(float *);

void main(void)
{

	char name [10][10];
	float mark_cs1[10];
	float mark_cs2[10];
	float mark_cs3[10];
	int ch_cs1[10];
	int ch_cs2[10];
	int ch_cs3[10];
	float gpa[10];
	int i,no_stud=0;

	printf("Enter number of student \n");
	scanf("%d",&no_stud);
	input_name(name,no_stud,mark_cs1,mark_cs2,mark_cs3,ch_cs1,ch_cs2,ch_cs3,gpa);

	
	for (i=0; i<no_stud; i++)
	   printf("You have entered %s whose GPA is %.2f\n",name[i],gpa[i]);

	  printf("Thank you \n");

}

void input_name(char name[][10], int stud, float mark_cs1[], float mark_cs2[], float mark_cs3[],int ch_cs1[],int ch_cs2[],int ch_cs3[],float gpa[])
{
	int i;

	for (i=0; i<stud; i++)
	{ printf("Enter a name \n");
	  scanf("%s",name[i]);
	  input_mark(mark_cs1,mark_cs2,mark_cs3,i);
	  input_credithr(ch_cs1,ch_cs2,ch_cs3,i);
	  calculate_gpa(mark_cs1,mark_cs2,mark_cs3,i,gpa,ch_cs1,ch_cs2,ch_cs3);;
	}
}

void input_mark(float mark1[], float mark2[], float mark3[], int i)
{

	 printf("Enter mark for course 1, 2 and 3 \n");
	 scanf("%f %f %f",&mark1[i], &mark2[i],&mark3[i]);
	
}

void calculate_gpa(float mark1[],float mark2[],float mark3[],int i,float gpa[],int ch_cs1[],int ch_cs2[],int ch_cs3[])
{
	float subgp1,subgp2,subgp3, totalcredit;

	totalcredit = ch_cs1[i]+ch_cs2[i]+ch_cs3[i];
	get_gradepoint(&mark1[i]);
	subgp1 = mark1[i] * (float)ch_cs1[i];
	get_gradepoint(&mark2[i]);
	subgp2 = mark2[i] * (float)ch_cs2[i];
	get_gradepoint(&mark3[i]);
	subgp3 = mark3[i] * (float)ch_cs3[i];

	gpa[i] = (subgp1+subgp2+subgp3)/totalcredit;
}

void input_credithr(int ch_cs1[],int ch_cs2[],int ch_cs3[],int i)
{
	 printf("Enter credit hour for course 1, 2 and 3 \n");
	 scanf("%d %d %d",&ch_cs1[i], &ch_cs2[i],&ch_cs3[i]);
}

void get_gradepoint(float *mark)
{	if (*mark > 80)
		*mark = 4.0;
	else if (*mark > 70)
		*mark = 3.0;
	else if (*mark > 60)
		*mark = 2.0;
	else if (*mark > 50)
		*mark = 1.0;
	else if (*mark > 0)
		*mark = 0;
}

L7Sqr · #2 13-Oct-2009, 12:17

One doesnt generally convert code to structure. Can you elaborate on what exactly it is you need?

WaltP · #3 13-Oct-2009, 23:55

Create a structure (student) containing these fields

CPP / C++ / C Code:

	char name [10][10];
	float mark_cs1[10];
	float mark_cs2[10];
	float mark_cs3[10];
	int ch_cs1[10];
	int ch_cs2[10];
	int ch_cs3[10];
	float gpa[10];

making the structure an array instead of the fields. Then access each field by, for example, student[i].ch_cs1 instead of ch_cs1[i].

Most function calls can be simplified by passing the structure instead of each array as you do now.

chekers · #4 15-Oct-2009, 05:51

This is the guideline,,,my lecturer ask me to convert the given coding with more easiest coding...short coding with structures ..

like when i execute the coding given...its ask me to enter number of student..
i enter 3....then it ask me to enter name, then enter result for 3 subject and then enter gpa for the 3 subjects given...the same repeated for 3 student and the result of the gpa is given at the end ..the example is like below..

Anyone can help me to create the same output using own coding...difference from the one i gave above...thank you alot frens....

chekers · #5 15-Oct-2009, 07:42

This is the question my lecturer gave to me...

Write a program that will read the name of a student and the three marks from three different courses entered by a user. For each course the credit hour is specified as 2, 3 or 4. The program continues to take these inputs until the maximum number of student (the maximum number is determined by the user). Store these inputs in the array. Calculate the GPA for each student based on the Grade Point below:

Marks Range Grade Grade point
80 - 100 A 4

70 - 79 B 3

60 - 69 C 2

50 - 59 D 1

< 49 F 0

Example:
Course A 87 A 3 credit hour
Course B 77 B 3 credit hour
Course C 65 C 3 credit hour
So, GPA = ((3 X 4) + (3 X 3) + (3 X 2)) / 9 = 3.00

fakepoo · #6 15-Oct-2009, 15:43

Try to think of the objects involved:

A STUDENT has a name three courses. Each COURSE has CREDIT HOURS and a MARK. So:

CPP / C++ / C Code:

struct Course
{
  int CreditHours; // 2, 3, or 4
  int Mark; // 0 to 100
};

struct Student
{
  char Name[32]; // Up to 31 characters long
  Course Courses[3]; // An array of 3 courses
};

// A few generic functions to show you how to access the structure
void PrintName(Student *student)
{
  printf(student->Name);
}

int AddMarks(Student *student)
{
  int sum = 0;
  for(int i=0;i<3;++i) sum += student->Courses[i].Mark;
  return sum;
}

int main()
{
  Student s;
  strcpy(s.Name, "chekers");
  
  s.Courses[0].CreditHours = 3;
  s.Courses[0].Mark = 68;

  s.Courses[1].CreditHours = 2;
  s.Courses[1].Mark = 55;

  s.Courses[2].CreditHours = 4;
  s.Courses[2].Mark = 81;

  printf("Sum of Marks = %d", AddMarks(&s));

  return 0;
}

chekers · #7 15-Oct-2009, 21:19

Quote:

Originally Posted by fakepoo

Try to think of the objects involved:

A STUDENT has a name three courses. Each COURSE has CREDIT HOURS and a MARK. So:

CPP / C++ / C Code:

struct Course
{
  int CreditHours; // 2, 3, or 4
  int Mark; // 0 to 100
};

struct Student
{
  char Name[32]; // Up to 31 characters long
  Course Courses[3]; // An array of 3 courses
};

// A few generic functions to show you how to access the structure
void PrintName(Student *student)
{
  printf(student->Name);
}

int AddMarks(Student *student)
{
  int sum = 0;
  for(int i=0;i<3;++i) sum += student->Courses[i].Mark;
  return sum;
}

int main()
{
  Student s;
  strcpy(s.Name, "chekers");
  
  s.Courses[0].CreditHours = 3;
  s.Courses[0].Mark = 68;

  s.Courses[1].CreditHours = 2;
  s.Courses[1].Mark = 55;

  s.Courses[2].CreditHours = 4;
  s.Courses[2].Mark = 81;

  printf("Sum of Marks = %d", AddMarks(&s));

  return 0;
}

I like your coding bro Fakepoo....but i dunno which header to use....i try execute in my vb6 and shows errors...and the file i must save for the assignment is in (.c)

I hope i can view the full start and end of the coding to make some studies on it...

Thanks alot fakepoo.........i really appreciate it

fakepoo · #8 16-Oct-2009, 07:25

In order to compile, you will need to include string.h (for strcpy)and stdio.h (for printf).

CPP / C++ / C Code:

#include <stdio.h>
#include <string.h>


struct Course
{
  int CreditHours; // 2, 3, or 4
  int Mark; // 0 to 100
};

struct Student
{
  char Name[32]; // Up to 31 characters long
  Course Courses[3]; // An array of 3 courses
};

// A few generic functions to show you how to access the structure
void PrintName(Student *student)
{
  printf(student->Name);
}

int AddMarks(Student *student)
{
  int sum = 0;
  for(int i=0;i<3;++i) sum += student->Courses[i].Mark;
  return sum;
}

int main()
{
  Student s;
  strcpy(s.Name, "chekers");
  
  s.Courses[0].CreditHours = 3;
  s.Courses[0].Mark = 68;

  s.Courses[1].CreditHours = 2;
  s.Courses[1].Mark = 55;

  s.Courses[2].CreditHours = 4;
  s.Courses[2].Mark = 81;

  printf("Sum of Marks = %d", AddMarks(&s));

  getchar();
  return 0;
}

Could the problem be that you are trying to compile a C program with a Visual Basic compiler?

chekers · #9 16-Oct-2009, 09:56

Yes bro fakepoo...im using visual basic 6.0 because in my course ,we using this compiler and save the file in .c format...

CPP / C++ / C Code:

#include <stdio.h>
#include <string.h>


struct Course
{
  int CreditHours; // 2, 3, or 4
  int Mark; // 0 to 100
};

struct Student
{
  char Name[32]; // Up to 31 characters long
  Course Courses[3]; // An array of 3 courses
};

void PrintName(Student*student);
{
  printf(student->Name);
}

int AddMarks(Student *student);
{
  int sum = 0;
  for(int i=0;i<3;++i) sum += student->Courses[i].Mark;
  return sum;
}

int main()
{
  Student s;
  strcpy(s.Name, "chekers");
  
  s.Courses[0].CreditHours = 3;
  s.Courses[0].Mark = 68;

  s.Courses[1].CreditHours = 2;
  s.Courses[1].Mark = 55;

  s.Courses[2].CreditHours = 4;
  s.Courses[2].Mark = 81;

  printf("Sum of Marks = %d", AddMarks(&s));

  getchar();
  return 0;
}

The errors shown is :

Quote:

Compiling...
g.c
C:\Users\Viper\Desktop\g.c(14) : error C2061: syntax error : identifier 'Course'
C:\Users\Viper\Desktop\g.c(15) : error C2059: syntax error : '}'
C:\Users\Viper\Desktop\g.c(17) : error C2143: syntax error : missing ')' before '*'
C:\Users\Viper\Desktop\g.c(17) : error C2143: syntax error : missing '{' before '*'
C:\Users\Viper\Desktop\g.c(17) : error C2059: syntax error : ')'
C:\Users\Viper\Desktop\g.c(18 ) : error C2449: found '{' at file scope (missing function header?)
C:\Users\Viper\Desktop\g.c(20) : error C2059: syntax error : '}'
C:\Users\Viper\Desktop\g.c(23) : error C2449: found '{' at file scope (missing function header?)
C:\Users\Viper\Desktop\g.c(27) : error C2059: syntax error : '}'
Error executing cl.exe.

g.exe - 9 error(s), 0 warning(s)

fakepoo · #10 16-Oct-2009, 10:05

Try compiling this:

CPP / C++ / C Code:

#include <stdio.h>

int main()
{
  printf("Hello World");
  getchar();
  return 0;
}

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