Trying to format the output display for Fibonacci number

tpetsovi · #1 16-Feb-2009, 08:49

Heres what he's asking for and I quote " Your table must display 6 numbers per row and use a spacing of 10 for each number"

I cant seem to figure it out and my brain is fry'd from staring at it a little help would be awesome.

CPP / C++ / C Code:

#include <iostream>
#include <iomanip>
using namespace std;

void main ()
{
	int Fib1 = 0;
	int Fib2 = 1;
	int Fib3;
	int counter = 3;
	cout << setw(10) << Fib1 << setw(10) << Fib2;

	do 
	{
		Fib3 = Fib1 + Fib2;
		cout << setw(10) << Fib3;
		Fib1 = Fib2;
		Fib2 = Fib3;
		counter++;
	}
	while (counter <= 40);
		cout << endl << endl;
}

I know I could have used a for loop as well but i didn't.

also you prob already see it can only display the first 40.

Howard_L · #2 16-Feb-2009, 11:17

First I must ask about:

CPP / C++ / C Code:

void main ()
{...

Does your instructor accept that? . . . I get:

Code:

g++ -Wall -W -pedantic coutformat-10.c -o coutformat-10.exe
coutformat-10.c:6: error: `main' must return `int'

Instead use:

CPP / C++ / C Code:

int main() :)

I'm not sure what your question was about specifically, but to print 6 values per row:
- Use a second: counter2 = 0;
- Inside your do-while loop: increment counter2 AND put an if( counter2 == 6 ) .
- If the if() returns true: print a newline and reset counter2 to 0 for next line.

ultrAslan · #3 17-Feb-2009, 00:14

I was gonna mention that part too.

CPP / C++ / C Code:

void main ()

zalezog · #4 18-Feb-2009, 11:58

Actually there is no need for a

CPP / C++ / C Code:

counter2

.
Instead,

CPP / C++ / C Code:

.
.
.
if (counter % 6==0)
  //go to a new line
 counter++;

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Trying to format the output display for Fibonacci number

Re: Trying to format the output display for Fibonacci number, I've tried everything.

Re: Trying to format the output display for Fibonacci number

Re: Trying to format the output display for Fibonacci number