Finding the Union, Intersection, Difference and Symmetric

khushal_kkk · #1 12-Nov-2008, 08:22

Given Below is my code for finding the Union , Intersection , Difference and Symetric but every time when i run my program i gets the forllwing

Code:

Invalid Enteries either in A or in B

and i want this sentence to be executed when the values of AUB or A intersection B are not Present In Universal set .

CPP / C++ / C Code:

void main()
{
int i,j,temp;
 int u[10];
 int a[5];
 int b[5];
 int aw[10]={0};
 int bw[10]={0};
 //clrscr();
  cout<<"Programme for union,intersection,difference,symmetric difference"<<endl;
  cout<<"Enter the values of Universal set i.e set U:";
  for(i=0; i<10; i++)
  cin>>u[i];
  cout<<"\n\t  U:\t{ ";
  for(i=0; i<10; i++)
  cout<<u[i]<<",";
  cout<<"\b"<<" }"<<endl<<endl;

  cout<<"Enter the values of set A:";
  for(i=0; i<5; i++)
  cin>>a[i];
  cout<<"\n\t  A:\t{ ";
  for(i=0; i<5; i++)
  cout<<a[i]<<",";
  cout<<"\b"<<" }"<<endl<<endl;

  cout<<"Enter the values of set B:";
  for(i=0; i<5; i++)
  cin>>b[i];
  cout<<"\n\t  B:\t{ ";
  for(i=0; i<5; i++)
  cout<<b[i]<<",";
  cout<<"\b"<<" }"<<endl<<endl;
  for(i=0;i<10;i++)
       {
	if((a[i]!=u[i])||(b[i]!=u[i]))
	temp=1;
	if(temp==1)
	cout<<endl<<endl<<"Invalid Enteries either in A or in B"<<endl;
	else

      for(i=0;i<5;i++)
   {
     for(j=0;j<10;j++)
      {
	if(a[i]==u[j])
	aw[j]=1;
	if(b[i]==u[j])
	bw[j]=1;
      }
   }


cout<<"\n\n\n  AUB:\t{ ";
  for(i=0;i<10;i++)
  if(aw[i]==1||bw[i]==1)
  cout<<u[i]<<",";
  cout<<"\b"<<" }"<<endl<<endl;

cout<<"\n\n\n\n  AnB:\t{ ";
  for(i=0;i<10;i++)
  if(aw[i]==1&&bw[i]==1)
   cout<<u[i]<<",";
  cout<<"\b"<<" }"<<endl<<endl;

 cout<<"\n\n\n\n  A-B:\t{ ";
  for(i=0;i<10;i++)
	  if(aw[i]==1 && bw[i] != 1)
		  cout<<u[i]<<",";
	  cout<<"\b"<<" }"<<endl<<endl;

cout<<"\n\n\n\n AcB:\t{ ";
  for(i=0;i<5;i++)
       if(aw[i]!=1 || bw[i]!=1)
		  cout<<u[i]<<",";
	  cout<<"\b"<<" }"<<endl<<endl;
  getch();


}
}

please help me as soon as possible

andylee · #2 13-Nov-2008, 00:52

I got to say than your code sucks.
I suggest you get Union of a and b to "a_b" firstly,
get Intersection of a and b to "a&b" secondly.
then check if the elements are Present In Universal set or not.

CPP / C++ / C Code:

int main()
{
	int a[ 5 ];
	int b[ 5 ];
	vector< int > c;
	int i = 0;
	for( i = 0; i < 5; ++i )
	{
		cin >> a[ i ];
	}
	for( i = 0; i < 5; ++i )
	{
		cin >> b[ i ];
	}
	sort( a, a + 5 );
	sort( b, b + 5 );
	set_intersection( a, a + 5, b, b + 5, back_inserter( c ) );
	cout << "intersection" << "\t" << endl ;
	for( i = 0; i < c.size(); ++i )
	{//intersection a&b
		cout << c[ i ] << "\t" ;
	}
	cout << endl;
	c.clear();
	set_union( a, a + 5, b, b + 5, back_inserter( c ) );
	cout << "union" << "\t" << endl ;
	for( i = 0; i < c.size(); ++i )
	{//union a+b
		cout << c[ i ] << "\t" ;
	}
	cout << endl;
	c.clear();
	set_difference( a, a + 5, b, b + 5, back_inserter( c ) );
	cout << "difference" << "\t" << endl ;
	for( i = 0; i < c.size(); ++i )
	{//difference : a-b
		cout << c[ i ] << "\t" ;
	}
	cout << endl;
	return 0;
}

WaltP · #3 13-Nov-2008, 00:53

Well, first thing is your formatting -- you need to make your code clearer.

Next, void main() is just plain wrong.

Then,

CPP / C++ / C Code:

  cout<<"\n\t  A:\t{ ";
  for(i=0; i<5; i++)
  cout<<a[i]<<",";
  cout<<"\b"<<" }"<<endl<<endl;

is probably not a good idea. This might be a cleaner way to output a list (and with better code formatting):

CPP / C++ / C Code:

  cout << "\n\t  A:\t{ ";
  for (i = 0; i < 4; i++)
  {
      cout << a[i] << ",";
  }
  cout << a[4] << " }" << endl << endl;

Here's where the actual coding problem comes in:

CPP / C++ / C Code:

  for(i=0;i<10;i++)
       {
	if((a[i]!=u[i])||(b[i]!=u[i]))

What's the value of a[6]? Doesn't the array only contain 5 values (0-4)?

That might help you figure out why you're getting the error.

Quote:

Originally Posted by khushal_kkk

please help me as soon as possible

You've been here long enough to know this request is frowned upon.

ocicat · #4 13-Nov-2008, 23:09

Quote:

Originally Posted by WaltP

Quote:

Originally Posted by khushal_kkk

please help me as soon as possible

You've been here long enough to know this request is frowned upon.

Seconded. Some would say rude too.

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Finding the Union, Intersection, Difference and Symmetric

Re: Finding the Union, Intersection, Difference and Symmetric

Re: Finding the Union, Intersection, Difference and Symmetric

Re: Finding the Union, Intersection, Difference and Symmetric