Convert month name to to month number

minwei86 · #1 10-Nov-2008, 11:33

i got this

weekday = (day+ 2*mth + 3*(mth+1)/5 + year + year/4 - year/100 + year/400 + 1) % 7;

but the whole thing will only work out when day,mth and year are integer..

but i wan the user to enter the mth in string format like "jan","feb" and etc.

how to gonna make it like jan = 1, feb = 2 so that when user enter jan, the compiler will know is 1 and do the formulae for me?

can someone guide me along??

all help is much appreciated.

Blake · #2 10-Nov-2008, 11:38

If you just want the compiler to recognize that jan = 1, feb = 2, etc, you can use macros, like this:

#define jan 1
#define feb 2

etc.

minwei86 · #3 10-Nov-2008, 11:53

hmm..so if user enter "jan" the compiler will recognise it as 1 rite, can teach me how i go along to implement it...

Blake · #4 10-Nov-2008, 12:03

No. Now you're talking about converting user input from a string to an integer at runtime. That's different from making the compiler recognize that jan = 1, feb = 2, etc. If you want to do it at runtime, the easiest thing to do would probably by to store the string equivalents of the month names in an array, and search the array for a match.

This should get you started:

CPP / C++ / C Code:

#include <string>

using namespace std;

string months [] = {"jan", "feb", "mar", "apr", "may", "jun", "jul", "aug", "sep", "oct", "nov", "dec"};

int getMonth(const string& abbrev)
{
  // loop through the array, and find the month that matches abbrev
}

minwei86 · #5 10-Nov-2008, 12:09

haha i tried that before...i get stuck while get started...cos i create a array of number from 1 to 12 like int mth[] = {1,2,3,4,5,6,7,8,9,10,11,12}; i intend to use pointer to point jan to 1 , something like that...but doesnt work well as pointer cant be use to point string to int..have to be same data type

Blake · #6 10-Nov-2008, 12:15

Why are you putting the numbers from 1 to 12 in an array? You want to search the array for the name of a month, not the number. Then add 1 to the index into the array to get the number of the month.

If the user enters "jun", for example, when you search through the array you find the string "jun" at months[5] and so you return 6.

minwei86 · #7 10-Nov-2008, 12:18

i think i get what u mean by it...how should i make it when i type "jun" it display 6?

Blake · #8 10-Nov-2008, 12:24

Just call the getMonth function (you'll need to finish implementing it

)

CPP / C++ / C Code:

#include <iostream>
#include <string>

using namespace std;

string months [] = {"jan", "feb", "mar", "apr", "may", "jun", "jul", "aug", "sep", "oct", "nov", "dec"};

int getMonth(const string& abbrev)
{
  // loop through the array and find the entry that matches abbrev
}

int main()
{
  string month;
  cout<<"Enter a month: ";
  cin>>month;
  cout<<getMonth(month);
}

If you don't want it to be case-sensitive, convert the input to lower case.

minwei86 · #9 10-Nov-2008, 13:31

CPP / C++ / C Code:

#include <iostream>
#include <string>

using namespace std;

string months [12] = {"jan", "feb", "mar", "apr", "may", "jun", "jul", "aug", "sep", "oct", "nov", "dec"};

int getMonth(string& month)
{
    int count = 0;

  for(int i = 0; i<12; i++)
  {
      if(month == months[i])
      count++;
  }
  return count;
}

int main()
{
  string month;
  cout<<"Enter a month: ";
  cin>>month;
  cout<<getMonth(month);
}

i try to do like this...i type jan it will return 1, but i type other it also return 1...why?

fakepoo · #10 10-Nov-2008, 13:59

Your variable count only gets incremented when it is equal to the input. Maybe just return i when that happens instead:

CPP / C++ / C Code:

int getMonth(string& month)
{
  for(int i = 0; i<12; i++)
  {
      if(month == months[i]) return i; // or return i+1, depending on what you want
  }
  return 0;
}

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Convert month name to to month number

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