Error C2106: '=' : left operand must be l-value

L_i_o_n · #1 22-Sep-2008, 22:06

The Program says: A long-distance carrier charges the following rates for telephone calls:

00:00-6:59 .12 per min
07:00-19:00 .55 per min
19:01-23:59 .35 per min

Write a program that asks for the starting time and the number of minutes of call, and displays the charges. The program should ask for the time to be entered as a floating point number in the form HH.MM. For example, 07:00 hours will be entered as 07.00, and 16:28 will be entered as 16:28.

Input validation: The program should not accept times that are greater than 23:59. Also, no number whose last two digits are greater than 59 should be accepted. Hint: Assuming num is a floating-point variable, the following expression will give you its fractional part:
num - static_cast<int>(num)

Here is my code Its half completed because I like to check and see if my logic works but if you have any alternative and much easier forms of code I would appreciate it very much Its due tommorow and it looks like im up tonight figureing this one out. I need help on this error that i get all the time.

c:\users\sign on\documents\visual studio 2008\projects\long distance calls\long distance calls\long_ distance_ calls.cpp(36) : error C2106: '=' : left operand must be l-value

Code:

CPP / C++ / C Code:

#include <iostream>
using namespace std;

int main()
{
	float number;
	float time;
	double rateOne=.12;
	double rateTwo=.55;
	double rateThree=.35;
	float charges;


	cout << "This program determines the total cost of your bill." << endl;
	cout << "Please enter the number of hours you talked your input should be between" << endl;
	cout << "0 and 23.59. Also the miniutes must be less than 60," << endl;
	cin >> time;

	if (time > 23.59)
	{
	cout << "Please enter a time between 0 and 23.59 where the whole numbers are hours." << endl;
	}
	if (time-static_cast<int>(time)>.59)
	{
		cout << "Please enter a valid amount of miniutes." <<endl;
	}
	else if (time > 19.01)
	{
	number = 23.59 - time;
	charges = rateOne*60*6*59 + rateTwo*13*60 + rateThree* number=static_cast<int>(number)*60 + rateThree*(number-static_cast<int>(number))/100;
	charges= static_cast<double>(charges);
	cout << charges << endl;
	}
	else if (time > 7.00)
	{
	charges= rateOne*60*6*59+rateTwo*(time=static_cast<int>(time))*60*time-static_cast<int>(time);
	cout << charges << endl;
	}
	


	
	


		system("Pause");

		return 0;
}

L_i_o_n · #2 22-Sep-2008, 22:08

Forgot to mention the error occurs at charges when it is first used in the if statement mixed with rate 1 etc.

ocicat · #3 22-Sep-2008, 22:39

Quote:

Originally Posted by L_i_o_n

c:\users\sign on\documents\visual studio 2008\projects\long distance calls\long distance calls\long_ distance_ calls.cpp(36) : error C2106: '=' : left operand must be l-value

Line 36 of your code:

CPP / C++ / C Code:

charges=rateOne*60*6*59+rateTwo*(time=static_cast<int>(time))*60*time-static_cast<int>(time);

...has two incorrect assignments (look for two equal signs, '='...).

In the future, please wrap your code with code tags ([cpp] before, & [/cpp] afterwards...) to both format your code & make it simpler for others you are hoping will spend their time reviewing.

L_i_o_n · #4 22-Sep-2008, 23:01

Thanks man I appreciate you helping me with the error but I got fustrated and solved it a different way feel free to review the code now for the next program I hope your on just in case I need help

CPP / C++ / C Code:

#include <iostream>
using namespace std;

int main()
{
	float number;			//Defines Number Of Hours Between A Certain Interval of Hours
	float time;
	double rateOne=.12;
	double rateTwo=.55;
	double rateThree=.35;
	double charges;
	int wholeNumber;		//Defines Number as a whole Number
	float fractionNumber;	//Defines Number as a fraction


	cout << "This program determines the total cost of your bill." << endl;
	cout << "Please enter the number of hours you talked your input should be between" << endl;
	cout << "0 and 23.59. Also the miniutes must be less than 60," << endl;
	cin >> time;

	if (time > 23.59)
	{
	cout << "Please enter a time between 0 and 23.59 where the whole numbers are hours." << endl;
	}
	if (time-static_cast<int>(time)> .6)
	{
		cout << "Please enter a valid amount of miniutes." <<endl;
	}
	else if (time > 19.01 && time < 23.59)
	{
	number = time-19.01;
	fractionNumber= number-static_cast<int>(number);
	wholeNumber= number=static_cast<int>(number);	
	charges= (rateOne*60*6+ rateOne*59)+(rateTwo*13*60)+(rateThree* fractionNumber*100) + rateThree * wholeNumber * 60;
	charges=static_cast<double>(charges);
	cout << "Your Fee is $" << charges << endl;
	}
	else if (time > 7.00 && time < 19.01)
	{
	number = time - 7;
	fractionNumber = number-static_cast<int>(number);
	wholeNumber = number=static_cast<int>(number);
	charges= (rateOne*60*6)+(rateOne*59) + (rateTwo * wholeNumber * 60) + (fractionNumber * rateTwo*100);
	cout << "Your Fee is $" << charges << endl;
	}
	else if (time >=0 && time <7.00)
	{
	number = time;
	fractionNumber = number-static_cast<int>(number);
	wholeNumber = number=static_cast<int>(number);
	charges = (rateOne * 60 * wholeNumber) + (rateOne * fractionNumber*100);
	cout << "Your Fee is $" << charges << endl;
	
	}
	


	
	


		system("Pause");

		return 0;
}

ocicat · #5 22-Sep-2008, 23:30

Quote:

Originally Posted by L_i_o_n

I hope your on just in case I need help

Recognize that this site is not a live site meaning that your questions can and/or will be answered in real-time. In general, there are enough people answering questions here such that you will likely receive some form of answer within 0.5 - 1 day.

The best thing you can do both for yourself & for future discussion is be very clear as to the problem you are experiencing, & posting minimal code which generates the error seen. You would be surprised at how many people expect us to be mind readers.

Good luck.

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