Using pointer as a parameter

nilusha6 · #1 28-Aug-2008, 03:13

I have a pointer variable in main function.(linked list)

i need to pass that pointer to a function.
in the function,it will change the pointer contents.(added new items)

But i need the original pointer as it is.

so, how can I use a copy of that pointer(link list) within that function.

actually i need to getseveral paths in a diagrem,path is starting from (0,0).
destination is (7,7).
I have to find all the posible paths.Thats y i used linked list.

So,I try to start from frist position. when path is divided , i need to get two different paths.So, i ll try to use that stroed linked list's 2 copies and want to store the rest.

So,can any 1 gv me any idea please.

fakepoo · #2 28-Aug-2008, 09:50

You should probably pass a pointer to that pointer:

CPP / C++ / C Code:

void AllocateArray( int **ppArray, int size )
{
  *pArray = (int*)calloc(size,sizeof(int));
}

int main()
{
  int *pArray;
  AllocateArray( &pArray, 10 );
  // ...
  free(pArray);
  return 0;
}

Or, if it is fairly simple, you could pass the pointer as an argument to the function and return it from the function like so:

CPP / C++ / C Code:

int *EditPointer( int *p )
{
  // do what you need to do to p
  return p;
}

int main()
{
  int x;
  int *p;
  p = &x;

  p = EditPointer( p );

  return 0;
}

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Using pointer as a parameter

Re: Using pointer as a parameter