C++ Nested loop coding

Evilrock · #1 10-Jul-2008, 06:46

Please help me with this.
i want to write a program to accept the number of digits from the user and then print all the combinations possible in that number of digits. the combinations should not repeat the particular number twice.
for example: if a users inputs 3 then the program shud print all possible combinations in 3 digit numbers ==> 123,456,789,124,125..... without repeating the number like==>111,112,211,221.
Please help me out with this as soon as possible.
thank you

ocicat · #2 10-Jul-2008, 08:49

Quote:

Originally Posted by Evilrock

Please help me out with this as soon as possible.

We can be quite forthcoming with suggestions, corrections, & insight if if it is clear that you have already put in effort to solve the problem. Otherwise, it can appear that you are simply dropping off homework assignments waiting for us to do the work for you.

You will learn more if you attempt the problem first.

Posting code also provides a great starting point for discussion as this helps frame what topics you seek clarification.

fakepoo · #3 10-Jul-2008, 10:45

Here is a routine that would print for input of 3. You will be required to change it to print for any number of digits.

CPP / C++ / C Code:

void PrintAllCombinationsOf3Digits()
{ int i,j,k;
  
  for(i=0;i<10;++i)
  { 
    for(j=0;j<10;++j)
    {
      for(k=0;k<10;++k)
      { 
        // Skip the repeaters
        if(i == j || i == k || j == k) continue;

        // Print the digits
        cout << i << j << k << endl;
      }
    }
  }
}

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C++ Nested loop coding

Re: C++ Nested loop coding ...plz help

Re: C++ Nested loop coding ...plz help