roll dice animation

slash24 · #1 03-Apr-2008, 01:20

Hello!
i have to write code for a dice roll by displaying the numbers 1 to 6 on the screen..
This is what i have done:

CPP / C++ / C Code:

int AnimOfDice() 
{
     int delay=1,later,die;   
     later=time(0)+delay;
     srand(time(0));
     cout<<"Number on dice is....  ";
     while(later!=time(0))
     {
     die = rand()%6+1;
     cout<<die;                    
     }
     return die;
}

is this the right way to do it?It doesnt work...

Blake · #2 03-Apr-2008, 05:40

I see 2 problems here.

1.

CPP / C++ / C Code:

while(later!=time(0))

Should be

CPP / C++ / C Code:

while(later < time(0))

Why? Because it's possible (although unlikely in this case since the body of the loop is so small) that we could skip right past the point where time(0) == later. Again, it's very unlikely that this will cause problems with your program, but it's important to understand the principle.

2.

I'm assuming that you don't want to display the results until after the time has passed. That means that you should do it after the while loop terminates:

CPP / C++ / C Code:

     while(later<time(0)) {}
     die = rand()%6+1;
     cout<<die;

davekw7x · #3 03-Apr-2008, 10:16

Quote:

Originally Posted by Blake

Should be

CPP / C++ / C Code:

while(later < time(0))

Shouldn't it be

CPP / C++ / C Code:

    while(later > time(0))

Quote:

Originally Posted by Blake

I'm assuming that you don't want to display the results until after the time has passed.

Since the function name is "Anim...," I would assume that some kind of animation is involved. See Footnote.

Maybe:

CPP / C++ / C Code:

int main()
{
    int value;
    value = AnimOfDice();
    cout << "value = " << value << endl;
    return 0;
}

int AnimOfDice()
{
    int delay = 1, later, die;
    later = time(0) + delay;
    srand(time(0));
    cout << "Number on die is.... ";
    while (later > time(0)) {
        die = (rand() % 6) + 1;
        cout << die << '\b'; // backspace over the previous number
    }
    cout << endl;
    return die;
}

If the terminal implementation supports a "backspace" character, this might give what was wanted. I mean, the '\b' special character is part of the C language standard, but not all terminals support it, so the actual action is implementation (and hardware) dependent. In other words: IWFMYMMV (It Works For Me---Your Mileage May Vary.)

Regards,

Dave

Footnote: Since the Original Poster didn't actually mention what was meant by "doesn't work," we are both guessing. Maybe I'm wrong.

To Original Poster: It might save some time and bandwidth if you would actually tell us
1. What did you expect to happen (or what did you want to happen).
2. What happened?
3. What do you not understand about the difference between 1 and 2.

I mean, why should we have to guess?

Final comment: The singular of "dice" is "die." If you have one, it's a "die." If you have two (or more), they are "dice."

slash24 · #4 03-Apr-2008, 10:25

well when i use the function as

x=AnimOfDice();

it works..

but when i use it in a loop

for(i=0;i<4;i++)

i get lots of numbers...

i need to display the dice roll for 4 players

davekw7x · #5 03-Apr-2008, 11:02

Quote:

Originally Posted by slash24

well ...

Well, "getting lots of numbers" doesn't really tell us much. Or maybe it's just me.

I'm not going to guess again. I respectfully suggest that you show us the code.

Then (and I hate to repeat myself) but:

1. Tell us what you expected to happen.
2. Tell us what happened.
3. Tell us what you don't understand about the difference between 1 and 2

Regards,

Dave

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roll dice animation

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