Greetings,

On my site, I link to other sites webcams, but sometimes those cams are down for what ever reason, and it returns a 404 error back to the window that is displaying the cam. Right now I just go in and modify a field in the database to display a static image for that webcam, but I have to know that its down.

I need something to automatically recognise that there is a 404 error and display the static image instead. Any suggestion of bits of code will help



Thanks,
Richard

You may want to write a script, run it as a cron job perhaps, that will send a request to the web site(s) at least once a day. Parse the response for the STATUS and log the results to a file.

To send a request, you can use the PHP function fsockopen. Look at the example code in this web page to get an idea: www.gidnetwork.com/b-54.html. Although I use the GET method -- to request the page -- you may use HEAD instead.

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