Ok well I'm trying to make a program that uses the pi formula and outputs 3 different answers. The formula is p = 4*(1 - (1/2i-1) + (1/2i+1). The 3 answers I need to output are when i = 100, 1000, and 100000. I need to start with i = 2 and each time through the loop another 2 gets added to i and will only output when it is at the 3 numbers; 100, 1000, and 100000. This is what I currently have and it does not work, I think I am way off with my whole code so any help would be great.

// Author :
// Date :
// Assignment :
// Compiler :
// Command line :
// Collaborators :

#include <iostream>
using namespace std;

int main(){

// Variable declarations
double pione;
double pitwo;
double pithree;
int i = 2;



// Figure out cost of tuition for child
do{
if (i == 100);
if (i == 1000);
if (i == 100000);
i += 2;

}

while (i <= 100000){
pione = 4 *(1-(1/(2i-1) + (1/(2i + 1);
pitwo = 4 *(1-1/(2i-1) + (1/(2i + 1);
pithree = 4 *(1 - (1/(2i-1) + (1/(2i+1);

}

//tell user how much pi equals when i is 100, 1000, and 100000
cout << " When i=100 pi = " << pione << endl;
cout << " When i=1000 pi = " << pitwo << endl;
cout << " When i=100000 pi = " << pithree << endl;




return 0;
}

Your code is "messed up" and you definitely need to read the guidelines.



...will at least compile, but I think that you need to seriously look at your calculations, as I doubt that it is what you want from the calculations.


:davis: