Console Will Not Stay Open

doom1992 · #1 22-Jul-2007, 05:53

hi there people, for some strange reason my code will not stay open what do i add in to get the console to stay open. Here is my code

CPP / C++ / C Code:

#include <iostream>

int age;

int main () {
    std::cout <<"What is your age";
    std::cin >> age;
    
    if (age >= 18) {
            std::cout <<"You can vote";
            }
            else {
                 std::cout <<"You are to you to vote";
                 }
                 
                 std::cout <<"Press Enter To Exit";
                 std::cin.get();
                 return 0;
}

Kimmo · #2 22-Jul-2007, 06:10

Did you read at all what I said in your other similar thread?

http://www.gidforums.com/t-14967.html

CPP / C++ / C Code:

std::cin >> age;
std::cin.get();

You input "18[ENTER]". The first statement reads 18, [ENTER] left. The second statement reads [ENTER].

Run console programs from the console. And by running from the console I mean "open the console, navigate to the directory that contains your program, execute." Or put system("PAUSE") at the end, but I find that to be useless complicating of matters.

Now if there are things you don't get in this, ask them in this thread. Someone around here most probably has the answers.

EDIT

If you don't want to run from console, you can add something like this at the end

CPP / C++ / C Code:

while (std::cin.get() != '\n')        // reads up until and including newline
   continue;
std::cin.get();                         // waits for input

doom1992 · #3 22-Jul-2007, 06:26

yhanks the system puase worked, and btw i did open it from the root

Kimmo · #4 22-Jul-2007, 06:46

Quote:

Originally Posted by doom1992

yhanks the system puase worked, and btw i did open it from the root

I don't know what you mean by opening it from the root.

But if you run the programs from the console, then why would you want to put something like system("PAUSE") at the end of the program? What is the use of keeping the program open?

doom1992 · #5 22-Jul-2007, 07:04

hi there, i want to use a if else statment to make a application. I would like to make an application where i can ask the user for a password and if the password is correct there will be a console out saying well done, if it is not correct it will say better look next time, could you please quickly write me this little application and reply to this post.

Thanks

WaltP · #6 22-Jul-2007, 22:47

Quote:

Originally Posted by doom1992

yhanks the system puase worked, and btw i did open it from the root

Wrong solution. Here's why...

BentFX · #7 22-Jul-2007, 23:55

I'm no pro, but some searching came up with this... http://forums.devarticles.com/c-c-help-52/cin-get-9130.html

Two solutions that seemed to be offered were... send cout an << endl; or call cin.ignore(); to flush out buffers before your cin.get();

Hope that is helpful

Skip

GrapeApe · #8 11-Aug-2007, 14:01

Add this below your includes :

CPP / C++ / C Code:

void exit() 
{ 
  std::cout<<"Press [Enter] to Exit . . .";
  std::cin.get();
}

Remove this from you code:

CPP / C++ / C Code:

std::cout <<"Press Enter To Exit";
                 std::cin.get();
                 return 0;

And add this in their place:

CPP / C++ / C Code:

   exit();

   std::cin.get();

I am very new to c++ and it took me a awhile to find this solution but it works for me.

Kimmo · #9 11-Aug-2007, 14:36

Quote:

Originally Posted by GrapeApe

it works for me.

Actually it doesn't. The function call is actually pretty pointless. It's equivalent to just writing

CPP / C++ / C Code:

std::cout<<"Press [Enter] to Exit . . .";
std::cin.get();
std::cin.get();

cin.get() reads ONE char. One char. If you have one extra char in input stream waiting, then you're lucky. If you have two, then you're out of luck.

Did you try doing some simple testing like entering "5.7"?

Take a look at this thread: http://www.gidforums.com/t-15133.html

There is also a bit more advanced stringstream stuff which Dave explained, but also other useful hints. Dave also explains some basics of cin functionality, which every (decent, beginner-level) C++ book should cover. Problem nowadays, though, seems to be that no one buys books. Except us oldies.

GrapeApe · #10 12-Aug-2007, 10:28

I apologize I didn't understand the question and my answer was SLOPPY.
This is what he is looking for.

CPP / C++ / C Code:

#include <iostream>
#include <iomanip>

using namespace std;


void getinput ( int &age)
   {
    std::cout <<"What is your age you:";
    std::cin >> age;
    cin.ignore(100, '\n');  
   } 
    


int main () {  

     int age = 0;

   do

        {      
          getinput(age);
        
         if ( age < 18 )
              {
            std::cout <<"You are to young to vote.\n";
              }
           
        } while ( age < 18 );



   if (age >= 18 ) {
            std::cout <<"You can vote! \n";
            }

        
  std::cout<<"Press [Enter] Exit...";
std::cin.get();
std::cin.get();


}

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