button from code to db

pembomassive · #1 10-Mar-2007, 11:51

Hi I have a guest area where I want people to sign up on a page and have completed the fundamentals, but not the button. I want once the button is clicked on it to take the personal information into the database from the page? Any ideas

pembomassive · #2 14-Mar-2007, 05:09

?????

So if I have a form completed say if you were signing up as a member how would this information be taken into the db and submitt

admin · #3 14-Mar-2007, 06:02

When the form is submitted (e.g. via the post method), the target script will receive the user submitted data inside the $_POST variable/array.

To understand how this works, look at the sample documents below...

For example, the web page with the form is test_form.htm:

HTML Code:


<html>
	<head>
		<title>The form</title>
	</head>
	<body>
		<form name="formTest" id="formTest" method="post" action="test_save.php">
			<p>Username: <input type="text" name="inputUsername" id="inputUsername" value="" /></p>
			<p>Email: <input type="text" name="inputEmail" id="inputEmail" value="" /></p>
			<p><input type="submit" name="inputSave" id="inputSave" value="Save" /></p>
		</form>
	</body>
</html>

Looking at the form, you will see that all the data is destined for test_save.php. When the user fills in her data and submits the form, the data she submitted will be passed to this script.

The test_save.php script can look something like this:

PHP Code:


<?php


    if( $_POST )
    {
        echo '<pre>';
        print_r( $_POST );
        die( '</pre>' );

    }
    else
    {
        die( "<p>Sorry, please fill-in your data in this <a href='test_form.htm'>form</a>.</p>" );
    }
?>

The $_POST array would look like this:

$_POST['inputUsername'] = 'Data submitted by the user appears here';
$_POST['inputEmail'] = 'Data submitted by the user appears here';
$_POST['inputSave'] = 'Save';

Once you figure out how to handle user submitted data from within a PHP script, you can ask us about getting it all into a MySQL database table.

I hope I have not misunderstood your question.

pembomassive · #4 22-Mar-2007, 07:39

hi the first part i adapted and appears to work the second is not, think am prob doing wrong can u take a look at this for me please?

<html>
<head>

<body bgcolor="#99CCCC">

<link rel="stylesheet" type="text/css"
href="cssformat.php" />

<h2>Please enter your personal details</h2>
<hr>

<form name="formTest" id="guest" method="post" action="update.php">
<p>First name: <input type="text" name="inputfirstName" id="inputUsername" value="" /></p>
<p>Last name: <input type="text" name="inputlastName" id="inputEmail" value="" /></p>
<p>Gender: <select>
<option>Male</option>
<option>Female</option>
</select></p>
<p>Country: <select>
<option>Australia</option>
<option>Canada</option>
<option>France</option>
<option>India</option>
<option>New Zealand</option>
<option>United Kingdom</option>
<option>United Stated</option>
<option>Other</option>
</select></P>
<p>County: <input type="text" name="inputcounty" id="inputUsername" value="" /></p>
<p>Email: <input type="text" name="inputemail" id="inputUsername" value="" /></p>
<p><input type="submit" name="inputSave" id="inputSave" value="Save" /></p>
</form>

</body>
</html>#

--------------------------------------------------------------------------part two

<?php

if($_POST)
{
echo'<pre>';
print_r( $_POST );
die( '</pre>' );

}
else
{
die( "<p>Sorry, please fill-in your data in this <a href='test_form.htm'>form</a>.</p>" );
}

$_POST['fistName'] = 'Data submitted by user appears here';
$_POST['lastName'] = 'Data submitted by user appears here';
$_POST['gender'] = 'gender selction appears here';
$_POST['country'] = 'country selection appears here';
$_POST['county'] = 'Data submitted by user appears here';
$_POST['email'] = 'Data submitted by user appears here';

?>

pembomassive · #5 26-Mar-2007, 05:27

???????????????/

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button from code to db

Re: button from code to db

Re: button from code to db

Re: button from code to db

Re: button from code to db