three dimensional array

tufan · #1 02-Mar-2007, 16:04

i used a three dimensional vector in my program.But while accesing it with [] operator ,i'm living problem.It gives no problem while compiling but when it runned gives a access violation problem.i think after two dimension the use of [] is outbounded.here's my vector:
vector<int> kod;
vector<vector<int> > lines;
vector<vector<vector<int> > > nums;

davekw7x · #2 02-Mar-2007, 19:07

Quote:

Originally Posted by tufan

i used a three dimensional vector in my program.But while accesing it with [] operator ,i'm living problem.It gives no problem while compiling but when it runned gives a access violation problem.i think after two dimension the use of [] is outbounded.here's my vector:
vector<int> kod;
vector<vector<int> > lines;
vector<vector<vector<int> > > nums;

Two things to remember (but they are really the same thing):

1. The overloaded [] operator does not do bounds checking.

2. You must have the correct sizes of vectors before you can reference the elements with the [] operator.

I'll create and initialize a 3-d vector. I do it in stages and I use typdefs to try to keep my sanity, such as it is.

CPP / C++ / C Code:

#include <iostream>
#include <vector>

using namespace std;

typedef vector<int> intVector;
typedef vector<intVector> int2dVector;
typedef vector<int2dVector> int3dVector;

int main()
{
    int xSiz = 2;
    int ySiz = 3;
    int zSiz = 4;

    intVector   kod(zSiz, 0);     // 1D: size=xSiz, initialized with zeros
    int2dVector lines(ySiz, kod); // 2D: size=ySiz, initialized with 1D vectors
    int3dVector nums(xSiz, lines);// 3D: size=zSiz, initialized with 2D vectors
    unsigned i, j, k;

    int x = 0;

    for (i = 0; i < nums.size(); i++) {
        for (j = 0; j < nums[i].size(); j++) {
            for (k = 0; k < nums[i][j].size(); k++) {
                nums[i][j][k] = x++;
            }
        }
    }

    for (i = 0; i < nums.size(); i++) {
        for (j = 0; j < nums[i].size(); j++) {
            for (k = 0; k < nums[i][j].size(); k++) {
                cout << "nums[" 
                     << i << "]["
                     << j << "][" 
                     << k << "]= "
                     << nums[i][j][k] << endl;
            }
        }
    }
    return 0;
}

Output:

Code:

nums[0][0][0]= 0
nums[0][0][1]= 1
nums[0][0][2]= 2
nums[0][0][3]= 3
nums[0][1][0]= 4
nums[0][1][1]= 5
nums[0][1][2]= 6
nums[0][1][3]= 7
nums[0][2][0]= 8
nums[0][2][1]= 9
nums[0][2][2]= 10
nums[0][2][3]= 11
nums[1][0][0]= 12
nums[1][0][1]= 13
nums[1][0][2]= 14
nums[1][0][3]= 15
nums[1][1][0]= 16
nums[1][1][1]= 17
nums[1][1][2]= 18
nums[1][1][3]= 19
nums[1][2][0]= 20
nums[1][2][1]= 21
nums[1][2][2]= 22
nums[1][2][3]= 23

Regards,

Dave

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three dimensional array

Re: three dimensional array