display ascii

abakws · #1 11-Nov-2006, 08:50

here is the code:

PHP Code:


<?

for($i=0;$i<255;$i++)
{
    $char=chr($i);
    echo $char . "\t";
}
?>

this code doesnt display what i want to because chr()'s syntax is "string chr ( int ascii )" so the 'ascii' variable must be 'int' and in my code $i is string... how do i convert the string i into integer i?

solved:

this one works

PHP Code:


<?

for($i=0;$i<255;$i++)
{
    $char=chr($i);
    echo $i . "=" . $char . "<br>";
}


?>

however i cant figure it out why the first one doesnt work... oh yeah and sorry for that stupid question about converting from string to integer

"Variables in PHP are represented by a dollar sign followed by the name of the variable"

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